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ÔÅÄÅÐÀËÜÍÀß ÍÀËÎÃÎÂÀß ÑËÓÆÁÀ

 

ÏÈÑÜÌÎ

îò 16 ìàÿ 2006 ã. N ØÑ-6-05/504@

 

Î ÄÎÂÅÄÅÍÈÈ ÊÎÍÒÐÎËÜÍÛÕ ÑÎÎÒÍÎØÅÍÈÉ ÏÎÊÀÇÀÒÅËÅÉ ÔÎÐÌÛ

ÄÀÍÍÛÕ ÎÁ ÈÑ×ÈÑËÅÍÍÛÕ ÑÓÌÌÀÕ ÅÑÍ Ñ ÄÎÕÎÄΠÀÄÂÎÊÀÒÎÂ

 

 ñîîòâåòñòâèè ñ Ïðèêàçîì ÌÍÑ Ðîññèè îò 04.11.2003 N ÁÃ-4-06/30äñï@ íàïðàâëÿþòñÿ êîíòðîëüíûå ñîîòíîøåíèÿ ïîêàçàòåëåé ôîðìû Äàííûõ îá èñ÷èñëåííûõ ñóììàõ åäèíîãî ñîöèàëüíîãî íàëîãà ñ äîõîäîâ àäâîêàòîâ, óòâåðæäåííîé Ïðèêàçîì Ìèíôèíà Ðîññèè îò 06.02.2006 N 23í, äëÿ íàñòðîéêè øàáëîíîâ àâòîìàòèçèðîâàííîé êàìåðàëüíîé íàëîãîâîé ïðîâåðêè.

Óïðàâëåíèÿì ÔÍÑ Ðîññèè ïî ñóáúåêòàì Ðîññèéñêîé Ôåäåðàöèè äîâåñòè êîíòðîëüíûå ñîîòíîøåíèÿ äëÿ ïðèìåíåíèÿ â ðàáîòå íèæåñòîÿùèìè íàëîãîâûìè îðãàíàìè.

 

Çàìåñòèòåëü Ðóêîâîäèòåëÿ,

äåéñòâèòåëüíûé ãîñóäàðñòâåííûé

ñîâåòíèê íàëîãîâîé ñëóæáû ÐÔ

II ðàíãà

Ñ.Í.ØÓËÜÃÈÍ

 

 

 

 

 

                                                ÓÒÂÅÐÆÄÀÞ

                                       Çàìåñòèòåëü ðóêîâîäèòåëÿ

                                              ÔÍÑ Ðîññèè

                                    Äåéñòâèòåëüíûé ãîñóäàðñòâåííûé

                                       ñîâåòíèê íàëîãîâîé ñëóæáû

                                     Ðîññèéñêîé Ôåäåðàöèè II ðàíãà

                                     _________________ Ñ.Í.Øóëüãèí

                                     _____________________ 2006 ã.

 

                     ÊÎÍÒÐÎËÜÍÛÅ ÑÎÎÒÍÎØÅÍÈß

      ïîêàçàòåëåé ôîðì íàëîãîâîé è áóõãàëòåðñêîé îò÷åòíîñòè

 

Êîä ôîðìû îò÷åòíîñòè ïî ÊÍÄ      

1151081                     

Íàèìåíîâàíèå ôîðìû îò÷åòíîñòè    

Äàííûå îá èñ÷èñëåííûõ ñóììàõ
ÅÑÍ ñ äîõîäîâ àäâîêàòîâ     

Èäåíòèôèêàöèÿ   
äîêóìåíòà,      
óòâåðæäàþùåãî   
ôîðìó îò÷åòíîñòè

âèä äîêóìåíòà  

Äàííûå                      

äàòà óòâåðæäåíèÿ
ôîðìû îò÷åòíîñòè

06.02.2006                  

íîìåð äîêóìåíòà

23í                         

 

Èäåíòèôèêàöèÿ äî-
êóìåíòà, óòâåðæ-
äàþùåãî ïîñëåäíèå
èçìåíåíèÿ è äî- 
ïîëíåíèÿ â ôîðìó
îò÷åòíîñòè      

âèä äîêóìåíòà  

 

äàòà óòâåðæäåíèÿ
ôîðìû îò÷åòíîñòè

 

íîìåð äîêóìåíòà

 

 

Ïîäðàçäåëåíèå - ðàçðàáîò÷èê ÊÑ   

Óïðàâëåíèå åäèíîãî ñîöèàëü- 
íîãî íàëîãà                 

Ô.È.Î. èñïîëíèòåëÿ ïîäðàçäåëåíèÿ -
ðàçðàáîò÷èêà ÊÑ, òåëåôîí         

Øèëîâà Ëþáîâü Àíàòîëüåâíà   
913-03-70,                  
Êóçèíà Àíàñòàñèÿ Âëàäèìèðîâíà
Ãàâðèøîâà Âåðà Èâàíîâíà     
913-03-71                   

íîìåð âåðñèè ÊÑ                  

1                           

äàòà çàïîëíåíèÿ ôîðìû ÊÑ         

14.04.2006                  

 

ÊÎÍÒÐÎËÜÍÛÅ ÑÎÎÒÍÎØÅÍÈß

ïîêàçàòåëåé ôîðì íàëîãîâîé è áóõãàëòåðñêîé îò÷åòíîñòè

 

                               ┌───────────────┐

 Êîä ôîðìû îò÷åòíîñòè ïî ÊÍÄ   │1151081        │

                               └───────────────┘

 

                               ┌───────────────────────────────────────────────────────────┐

 Íàèìåíîâàíèå ôîðìû îò÷åòíîñòè │Äàííûå îá èñ÷èñëåííûõ ñóììàõ åäèíîãî                       │

                               │ñîöèàëüíîãî íàëîãà ñ äîõîäîâ àäâîêàòîâ                     │

                               └───────────────┬───────────────────────────────────────────┤

 Äàòà è íîìåð äîêóìåíòà,                       │Ïðèêàç Ìèíôèíà Ðîññèè                      │

 óòâåðæäàþùåãî ôîðìó îò÷åòíîñòè                │îò 06.02.2006 N 23í                        │

                                               └───────────────────────────────────────────┤

 Äàòà è íîìåð äîêóìåíòà, óòâåðæäàþùåãî                                                     │

 ïîñëåäíèå èçìåíåíèÿ è äîïîëíåíèÿ â ôîðìó îò÷åòíîñòè                                       │

┌─────────┬────────────────────────────┬───────────────────────────────────────────────────┤

│ Èñõîäíûå│  Êîíòðîëüíîå ñîîòíîøåíèå   │               ñëó÷àå íåâûïîëíåíèÿ ÊÑ:            │

│äîêóìåíòû│           (ÊÑ)             │                                                   │

├─────────┼────┬───────────────────────┼─────────┬─────────────┬───────────────────────────┤

│         │ N  │           ÊÑ          │âîçìîæíîå│ôîðìóëèðîâêà │   äåéñòâèÿ ïðîâåðÿþùåãî   │

│         │ï/ï │                       │íàðóøåíèå│  íàðóøåíèÿ  │                           │

│         │    │                       │çàêîíîäà-│             │                           │

│         │    │                       │òåëüñòâà │             │                           │

│         │    │                       │ÐÔ       │             │                           │

│         │    │                       │(ññûëêà) │             │                           │

├─────────┼────┼───────────────────────┼─────────┼─────────────┼───────────────────────────┤

│    1    │  2 │           3           │    4    │      5      │             6             │

├─────────┴────┴───────────────────────┴─────────┴─────────────┴───────────────────────────┤

│Ðàçäåë 1 "Ñóììû íàëîãà, ïîäëåæàùèå âûïëàòå â ôåäåðàëüíûé áþäæåò è ôîíäû îáÿçàòåëüíîãî     │

│ìåäèöèíñêîãî ñòðàõîâàíèÿ"                                                                 │

├─────────┬────────────────────────────────────────────────────────────────────────────────┤

│         │âíóòðèäîêóìåíòíûå ÊÑ                                                            │

├─────────┼────┬───────────────────────┬─────────┬─────────────┬───────────────────────────┤

│ÄàíÀäâÅÑÍ│1.1 │ÔÁ: ð. 1 ñòð. 030      │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │(040, 050, 060) = ð. 2 │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │ñòð. 0600 (0620, 0630, │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │0640) ãð. 3            │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

├─────────┼────┼───────────────────────┼─────────┼─────────────┼───────────────────────────┤

│ÄàíÀäâÅÑÍ│1.2 │ÔÔÎÌÑ: ð. 1 ñòð. 030   │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │(040, 050, 060) = ð. 2 │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │ñòð. 0600 (0620, 0630, │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │0640) ãð. 4            │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

├─────────┼────┼───────────────────────┼─────────┼─────────────┼───────────────────────────┤

│ÄàíÀäâÅÑÍ│1.3 │ÒÔÎÌÑ: ð. 1 ñòð. 030   │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │(040, 050, 060) = ð. 2 │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │ñòð. 0600 (0620, 0630, │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │0640) ãð. 5            │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

├─────────┴────┴───────────────────────┴─────────┴─────────────┴───────────────────────────┤

│Ðàçäåë 2 "Ðàñ÷åò åäèíîãî ñîöèàëüíîãî íàëîãà"                                              │

├─────────┬────────────────────────────────────────────────────────────────────────────────┤

│         │âíóòðèäîêóìåíòíûå ÊÑ                                                            │

├─────────┼────┬───────────────────────┬─────────┬─────────────┬───────────────────────────┤

│ÄàíÀäâÅÑÍ│1.4 │ð. 2 ñòð. 0110 ãð. 3 = │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │ð. 2 ñòð. (0120 + 0130 │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │+ 0140) ãð. 3          │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

├─────────┼────┼───────────────────────┼─────────┼─────────────┼───────────────────────────┤

│ÄàíÀäâÅÑÍ│1.5 │ð. 2 ñòð. 0100 ãð. 3 = │ÍÊ ÐÔ    │Çàíèæåíèå èëè│Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │ð. 2.1 ñòð. 040 ãð. 3  │ñò. 237  │çàâûøåíèå íà-│äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │                       │         │ëîãîâîé áàçû │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │         │ÅÑÍ â ÔÁ,    │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │ÔÔÎÌÑ, ÒÔÎÌÑ │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

├─────────┼────┼───────────────────────┼─────────┼─────────────┼───────────────────────────┤

│ÄàíÀäâÅÑÍ│1.6 │ð. 2 ñòð. 0210 ãð. 3   │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │(4, 5) = ð. 2 ñòð.     │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │(0220 + 0230 + 0240)   │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │ãð. 3 (4, 5)           │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

├─────────┼────┼───────────────────────┼─────────┼─────────────┼───────────────────────────┤

│ÄàíÀäâÅÑÍ│1.7 │Åñëè ð. 2.2 ñòð. 020   │ÍÊ ÐÔ    │Íåîáîñíîâàí- │Íàïðàâèòü óâåäîìëåíèå Àäâîá│

│         │    │ãð. 5 (6, 7, 8, 9) = 0,│ñò. 239, │íîå ïðèìåíå- │î ïðåäñòàâëåíèè ñïðàâîê    │

│         │    │òî ð. 2 ñòð. 0400      │ï. 1,    │íèå íàëîãîâûõ│(èëè èõ êîïèé), âûäàííûõ   │

│         │    │(0410, 0420, 0430,     │ïï. 1    │ëüãîò, ïî-   │ó÷ðåæäåíèÿìè ìåäèêî-ñîöè-  │

│         │    │0440) ãð. 3 = 0        │         │âëåêøåå çàíè-│àëüíîé ýêñïåðòèçû èëè ÂÒÝÊ,│

│         │    │                       │         │æåíèå ÅÑÍ â  │ñî ñðîêàìè èõ äåéñòâèÿ,    │

│         │    │                       │         │ÔÁ, ÔÔÎÌÑ,   │ïîäòâåðæäàþùèõ èíâàëèäíîñòü│

│         │    │                       │         │ÒÔÎÌÑ        │àäâîêàòîâ.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ â ñîîòâåò- │

│         │    │                       │         │             │ñòâèè ñ ï. 2 ñò. 101 ÍÊ ÐÔ │

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│Åñëè ð. 2.2 ñòð. 020 ãð. 5 - 9 > 0, òî: äîëæíû âûïîëíÿòüñÿ ÊÑ 1.8 - 1.12                  │

├─────────┬────┬───────────────────────┬─────────┬─────────────┬───────────────────────────┤

│ÄàíÀäâÅÑÍ│1.8 │ð. 2 ñòð. 0400 ãð. 3 = │ÍÊ ÐÔ    │Íåîáîñíîâàí- │Íàïðàâèòü óâåäîìëåíèå Àäâîá│

│         │    │ð. 2.2 ñòð. 020 ãð. 5  │ñò. 239, │íîå ïðèìåíå- │î ïðåäñòàâëåíèè ñïðàâîê    │

│         │    │                       │ï. 1,    │íèå íàëîãîâûõ│(èëè èõ êîïèé), âûäàííûõ   │

│         │    │                       │ïï. 1    │ëüãîò, ïî-   │ó÷ðåæäåíèÿìè ìåäèêî-ñîöè-  │

│         │    │                       │         │âëåêøåå çàíè-│àëüíîé ýêñïåðòèçû èëè ÂÒÝÊ,│

│         │    │                       │         │æåíèå ÅÑÍ â  │ñî ñðîêàìè èõ äåéñòâèÿ,    │

│         │    │                       │         │ÔÁ, ÔÔÎÌÑ,   │ïîäòâåðæäàþùèõ èíâàëèäíîñòü│

│         │    │                       │         │ÒÔÎÌÑ        │àäâîêàòîâ.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ â ñîîòâåò- │

│         │    │                       │         │             │ñòâèè ñ ï. 2 ñò. 101 ÍÊ ÐÔ │

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│ÄàíÀäâÅÑÍ│1.9 │ð. 2 ñòð. 0410 ãð. 3 = │ÍÊ ÐÔ    │Íåîáîñíîâàí- │Íàïðàâèòü óâåäîìëåíèå Àäâîá│

│         │    │ð. 2.2 ñòð. 020 ãð. 6  │ñò. 239, │íîå ïðèìåíå- │î ïðåäñòàâëåíèè ñïðàâîê    │

│         │    │                       │ï. 1,    │íèå íàëîãîâûõ│(èëè èõ êîïèé), âûäàííûõ   │

│         │    │                       │ïï. 1    │ëüãîò, ïî-   │ó÷ðåæäåíèÿìè ìåäèêî-ñîöè-  │

│         │    │                       │         │âëåêøåå çàíè-│àëüíîé ýêñïåðòèçû èëè ÂÒÝÊ,│

│         │    │                       │         │æåíèå ÅÑÍ â  │ñî ñðîêàìè èõ äåéñòâèÿ,    │

│         │    │                       │         │ÔÁ, ÔÔÎÌÑ,   │ïîäòâåðæäàþùèõ èíâàëèäíîñòü│

│         │    │                       │         │ÒÔÎÌÑ        │àäâîêàòîâ.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ â ñîîòâåò- │

│         │    │                       │         │             │ñòâèè ñ ï. 2 ñò. 101 ÍÊ ÐÔ │

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│ÄàíÀäâÅÑÍ│1.10│ð. 2 ñòð. 0420 ãð. 3 = │ÍÊ ÐÔ    │Íåîáîñíîâàí- │Íàïðàâèòü óâåäîìëåíèå Àäâîá│

│         │    │ð. 2.2 ñòð. 020 ãð. 7  │ñò. 239, │íîå ïðèìåíå- │î ïðåäñòàâëåíèè ñïðàâîê    │

│         │    │                       │ï. 1,    │íèå íàëîãîâûõ│(èëè èõ êîïèé), âûäàííûõ   │

│         │    │                       │ïï. 1    │ëüãîò, ïî-   │ó÷ðåæäåíèÿìè ìåäèêî-ñîöè-  │

│         │    │                       │         │âëåêøåå çàíè-│àëüíîé ýêñïåðòèçû èëè ÂÒÝÊ,│

│         │    │                       │         │æåíèå ÅÑÍ â  │ñî ñðîêàìè èõ äåéñòâèÿ,    │

│         │    │                       │         │ÔÁ, ÔÔÎÌÑ,   │ïîäòâåðæäàþùèõ èíâàëèäíîñòü│

│         │    │                       │         │ÒÔÎÌÑ        │àäâîêàòîâ.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ â ñîîòâåò- │

│         │    │                       │         │             │ñòâèè ñ ï. 2 ñò. 101 ÍÊ ÐÔ │

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│ÄàíÀäâÅÑÍ│1.11│ð. 2 ñòð. 0430 ãð. 3 = │ÍÊ ÐÔ    │Íåîáîñíîâàí- │Íàïðàâèòü óâåäîìëåíèå Àäâîá│

│         │    │ð. 2.2 ñòð. 020 ãð. 8  │ñò. 239, │íîå ïðèìåíå- │î ïðåäñòàâëåíèè ñïðàâîê    │

│         │    │                       │ï. 1,    │íèå íàëîãîâûõ│(èëè èõ êîïèé), âûäàííûõ   │

│         │    │                       │ïï. 1    │ëüãîò, ïî-   │ó÷ðåæäåíèÿìè ìåäèêî-ñîöè-  │

│         │    │                       │         │âëåêøåå çàíè-│àëüíîé ýêñïåðòèçû èëè ÂÒÝÊ,│

│         │    │                       │         │æåíèå ÅÑÍ â  │ñî ñðîêàìè èõ äåéñòâèÿ,    │

│         │    │                       │         │ÔÁ, ÔÔÎÌÑ,   │ïîäòâåðæäàþùèõ èíâàëèäíîñòü│

│         │    │                       │         │ÒÔÎÌÑ        │àäâîêàòîâ.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ â ñîîòâåò- │

│         │    │                       │         │             │ñòâèè ñ ï. 2 ñò. 101 ÍÊ ÐÔ │

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│ÄàíÀäâÅÑÍ│1.12│ð. 2 ñòð. 0440 ãð. 3 = │ÍÊ ÐÔ    │Íåîáîñíîâàí- │Íàïðàâèòü óâåäîìëåíèå Àäâîá│

│         │    │ð. 2.2 ñòð. 020 ãð. 9  │ñò. 239, │íîå ïðèìåíå- │î ïðåäñòàâëåíèè ñïðàâîê    │

│         │    │                       │ï. 1,    │íèå íàëîãîâûõ│(èëè èõ êîïèé), âûäàííûõ   │

│         │    │                       │ïï. 1    │ëüãîò, ïî-   │ó÷ðåæäåíèÿìè ìåäèêî-ñîöè-  │

│         │    │                       │         │âëåêøåå çàíè-│àëüíîé ýêñïåðòèçû èëè ÂÒÝÊ,│

│         │    │                       │         │æåíèå ÅÑÍ â  │ñî ñðîêàìè èõ äåéñòâèÿ,    │

│         │    │                       │         │ÔÁ, ÔÔÎÌÑ,   │ïîäòâåðæäàþùèõ èíâàëèäíîñòü│

│         │    │                       │         │ÒÔÎÌÑ        │àäâîêàòîâ.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ â ñîîòâåò- │

│         │    │                       │         │             │ñòâèè ñ ï. 2 ñò. 101 ÍÊ ÐÔ │

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│ÄàíÀäâÅÑÍ│1.13│ð. 2 ñòð. 0410 ãð. 3 = │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │ð. 2 ñòð. (0420 + 0430 │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │+ 0440) ãð. 3          │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│1.14│ð. 2 ñòð. 0500 ãð. 3 <=│ÍÊ ÐÔ    │Çàâûøåíèå    │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │ð. 2 ñòð. 0400 ãð. 3 x │(ñò. 56, │ÅÑÍ, íå ïîä- │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │5,3% / 100%            │ï. 2,    │ëåæàùåãî     │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │ñò. 239, │óïëàòå â ÔÁ â│ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │ï. 1,    │ñâÿçè ñ ïðè- │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │ïï. 1,   │ìåíåíèåì íà- │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │2,       │ëîãîâûõ ëüãîò│êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │ñò. 243, │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │ï. 1)    │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│1.15│ð. 2 ñòð. 0500 ãð. 4 <=│ÍÊ ÐÔ    │Çàâûøåíèå    │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │ð. 2 ñòð. 0400 ãð. 3 x │(ñò. 56, │ÅÑÍ, íå ïîä- │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │0,8% / 100%            │ï. 2,    │ëåæàùåãî     │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │ñò. 239, │óïëàòå â     │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │ï. 1,    │ÔÔÎÌÑ â ñâÿçè│äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │ïï. 1,   │ñ ïðèìåíåíèåì│øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │2,       │íàëîãîâûõ    │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │ñò. 243, │ëüãîò        │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │ï. 1)    │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

├─────────┼────┼───────────────────────┼─────────┼─────────────┼───────────────────────────┤

│ÄàíÀäâÅÑÍ│1.16│ð. 2 ñòð. 0500 ãð. 5 <=│ÍÊ ÐÔ    │Çàâûøåíèå    │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │ð. 2 ñòð. 0400 ãð. 3 x │(ñò. 56, │ÅÑÍ, íå ïîä- │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │1,9% / 100%            │ï. 2,    │ëåæàùåãî     │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │ñò. 239, │óïëàòå â     │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │ï. 1,    │ÒÔÎÌÑ â ñâÿçè│äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │ïï. 1,   │ñ ïðèìåíåíèåì│øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │2,       │íàëîãîâûõ    │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │ñò. 243, │ëüãîò        │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │ï. 1)    │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│1.17│ð. 2 ñòð. 0510 ãð. 3   │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │(4, 5) = ð. 2 ñòð.     │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │(0520 + 0530 + 0540)   │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │ãð. 3 (4, 5)           │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│1.18│ð. 2 ñòð. 0600 ãð. 3   │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │(4, 5) = ð. 2 ñòð.     │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │(0200 - 0500) ãð. 3    │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │(4, 5)                 │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│1.19│ð. 2 ñòð. 0610 ãð. 3   │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │(4, 5) = ð. 2 ñòð.     │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │(0620 + 0630 + 0640)   │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │ãð. 3 (4, 5)           │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│1.20│ð. 2 ñòð. 0610 ãð. 3   │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │(4, 5) = ð. 2 ñòð.     │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │(0210 - 0510) ãð. 3    │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │(4, 5)                 │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│1.21│ð. 2 ñòð. 0620 ãð. 3   │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │(4, 5) = ð. 2 ñòð.     │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │(0220 - 0520) ãð. 3    │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │(4, 5)                 │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│1.22│ð. 2 ñòð. 0630 ãð. 3   │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │(4, 5) = ð. 2 ñòð.     │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │(0230 - 0530) ãð. 3    │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │(4, 5)                 │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│1.23│ð. 2 ñòð. 0640 ãð. 3   │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │(4, 5) = ð. 2 ñòð.     │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │(0240 - 0540) ãð. 3    │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │(4, 5)                 │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│         │ìåæäîêóìåíòíûå ÊÑ                                                               │

├─────────┼────┬───────────────────────┬─────────┬─────────────┬───────────────────────────┤

│ÄàíÀäâÅÑÍ│2.1 │äàíÀäâÅÑÍ ð. 2         │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│ðÅÑÍ çà  │    │ñòð. 0100 ãð. 3 =      │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│9 ìåñ.   │    │äàíÀäâÅÑÍ ð. 2         │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │ñòð. 0110 ãð. 3 + ðÅÑÍ │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │çà 9 ìåñ. ð. 2         │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │ñòð. 0100 ãð. 3 (5, 6) │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│2.2 │äàíÀäâÅÑÍ ð. 2         │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│ðÅÑÍ çà  │    │ñòð. 0200 ãð. 3 (4, 5) │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│9 ìåñ.   │    │= äàíÀäâÅÑÍ ð. 2       │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │ñòð. 0210 ãð. 3 (4, 5) │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │+ ðÅÑÍ çà 9 ìåñ. ð. 2  │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │ñòð. 0200 ãð. 3 (5, 6) │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│2.3 │äàíÀäâÅÑÍ ð. 2         │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│ðÅÑÍ çà  │    │ñòð. 0400 ãð. 3 =      │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│9 ìåñ.   │    │äàíÀäâÅÑÍ ð. 2         │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │ñòð. 0410 ãð. 3 + ðÅÑÍ │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │çà 9 ìåñ. ð. 2         │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │ñòð. 0400 ãð. 3 (5, 6) │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│2.4 │äàíÀäâÅÑÍ ð. 2         │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│ðÅÑÍ çà  │    │ñòð. 0500 ãð. 3 (4, 5) │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│9 ìåñ.   │    │= äàíÀäâÅÑÍ ð. 2       │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │ñòð. 0510 ãð. 3 (4, 5) │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │+ ðÅÑÍ çà 9 ìåñ. ð. 2  │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │ñòð. 0500 ãð. 3 (5, 6) │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│2.5 │äàíÀäâÅÑÍ ð. 2         │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│ðÅÑÍ çà  │    │ñòð. 0600 ãð. 3 (4, 5) │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│9 ìåñ.   │    │= äàíÀäâÅÑÍ ð. 2       │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │ñòð. 0610 ãð. 3 (4, 5) │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │+ ðÅÑÍ çà 9 ìåñ. ð. 2  │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │ñòð. 0600 ãð. 3 (5, 6) │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│Ðàçäåë 2.1 "Ðàñïðåäåëåíèå íàëîãîâîé áàçû (ñòðîêà 0100) è ÷èñëåííîñòè àäâîêàòîâ ïî         │

│èíòåðâàëàì øêàëû ðåãðåñèè"                                                                │

├─────────┬────────────────────────────────────────────────────────────────────────────────┤

│         │âíóòðèäîêóìåíòíûå ÊÑ                                                            │

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│ÄàíÀäâÅÑÍ│1.24│ð. 2.1 ñòð. 010 ãð. 3  │ÍÊ ÐÔ    │Çàâûøåíèå íà-│Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │/ ð. 2.1 ñòð. 010 ãð. 4│ñò. 241  │ëîãîâîé áàçû │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │<= 280000              │         │ïî ÅÑÍ â ÔÁ, │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │         │ÔÔÎÌÑ, ÒÔÎÌÑ │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │è (èëè) çàíè-│äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │æåíèå ÷èñëåí-│øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │íîñòè ôèçè-  │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │÷åñêèõ ëèö   │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │äëÿ ðàñ÷åòà  │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │ÅÑÍ â ÔÁ,    │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │ÔÔÎÌÑ, ÒÔÎÌÑ │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

├─────────┼────┼───────────────────────┼─────────┼─────────────┼───────────────────────────┤

│ÄàíÀäâÅÑÍ│1.25│ð. 2.1 ñòð. 020 ãð. 3  │ÍÊ ÐÔ    │Çàâûøåíèå íà-│Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │/ ð. 2.1 ñòð. 020 ãð. 4│ñò. 241  │ëîãîâîé áàçû │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │<= 600000              │         │ïî ÅÑÍ â ÔÁ, │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │         │ÔÔÎÌÑ, ÒÔÎÌÑ │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │è (èëè) çàíè-│äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │æåíèå ÷èñëåí-│øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │íîñòè ôèçè-  │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │÷åñêèõ ëèö   │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │äëÿ ðàñ÷åòà  │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │ÅÑÍ â ÔÁ,    │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │ÔÔÎÌÑ, ÒÔÎÌÑ │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│1.26│Åñëè ð. 2.1 ñòð. 050   │ÍÊ ÐÔ    │Çàâûøåíèå íà-│Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │ãð. 4 = 0, òî:         │ñò. 241  │ëîãîâîé áàçû │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │ð. 2.1 ñòð. 021 ãð. 3 /│         │ïî ÅÑÍ â ÔÁ, │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │ð. 2.1 ñòð. 021 ãð. 4 =│         │ÔÔÎÌÑ, ÒÔÎÌÑ │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │280000                 │         │è (èëè) çàíè-│äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │æåíèå ÷èñëåí-│øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │íîñòè ôèçè-  │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │÷åñêèõ ëèö   │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │äëÿ ðàñ÷åòà  │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │ÅÑÍ â ÔÁ,    │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │ÔÔÎÌÑ, ÒÔÎÌÑ │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│1.27│Åñëè ð. 2.1 ñòð. 050   │ÍÊ ÐÔ    │Çàâûøåíèå íà-│Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │ãð. 4 > 0, òî:         │ñò. 241  │ëîãîâîé áàçû │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │ð. 2.1 ñòð. 021 ãð. 3 /│         │ïî ÅÑÍ â ÔÁ, │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │ð. 2.1 ñòð. 021 ãð. 4  │         │ÔÔÎÌÑ, ÒÔÎÌÑ │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │<= 280000              │         │è (èëè) çàíè-│äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │æåíèå ÷èñëåí-│øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │íîñòè ôèçè-  │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │÷åñêèõ ëèö   │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │äëÿ ðàñ÷åòà  │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │ÅÑÍ â ÔÁ,    │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │ÔÔÎÌÑ, ÒÔÎÌÑ │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

├─────────┼────┼───────────────────────┼─────────┼─────────────┼───────────────────────────┤

│ÄàíÀäâÅÑÍ│1.28│ð. 2.1 ñòð. 020 ãð. 3 =│ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │ð. 2.1 ñòð. (021 + 022)│         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │ãð. 3                  │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│1.29│ð. 2.1 ñòð. 020 ãð. 4 =│ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │ð. 2.1 ñòð. 021 ãð. 4  │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │                       │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

├─────────┴────┴───────────────────────┴─────────┴─────────────┴───────────────────────────┤

│Äëÿ àäâîêàòñêèõ îáðàçîâàíèé, íå èìåþùèõ àäâîêàòîâ, ïåðåøåäøèõ èç äðóãèõ àäâîêàòñêèõ       │

│îáðàçîâàíèé (îáîñîáëåííûõ ïîäðàçäåëåíèé àäâîêàòñêèõ îáðàçîâàíèé, îòâå÷àþùèõ òðåáîâàíèÿì   │

│ï. 8 ñò. 243 ÍÊ ÐÔ), ó êîòîðûõ ð. 2.1 ñòð. 050 ãð. 4 = 0, âûïîëíÿåòñÿ ÊÑ 1.30             │

├─────────┬────┬───────────────────────┬─────────┬─────────────┬───────────────────────────┤

│ÄàíÀäâÅÑÍ│1.30│ð. 2.1 ñòð. 030 ãð. 3  │ÍÊ ÐÔ    │Çàíèæåíèå íà-│Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │/ ð. 2.1 ñòð. 030 ãð. 4│ñò. 241  │ëîãîâîé áàçû │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │> 600000               │         │ïî ÅÑÍ â ÔÁ, │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │         │ÔÔÎÌÑ, ÒÔÎÌÑ │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │è (èëè) çàâû-│äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │øåíèå ÷èñëåí-│øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │íîñòè ôèçè-  │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │÷åñêèõ ëèö   │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │äëÿ ðàñ÷åòà  │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │ÅÑÍ â ÔÁ,    │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │ÔÔÎÌÑ, ÒÔÎÌÑ │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│Äëÿ àäâîêàòñêèõ îáðàçîâàíèé, èìåþùèõ àäâîêàòîâ, ïåðåøåäøèõ èç äðóãèõ àäâîêàòñêèõ          │

│îáðàçîâàíèé (îáîñîáëåííûõ ïîäðàçäåëåíèé àäâîêàòñêèõ îáðàçîâàíèé, îòâå÷àþùèõ òðåáîâàíèÿì   │

│ï. 8 ñò. 243 ÍÊ ÐÔ), ó êîòîðûõ ð. 2.1 ñòð. 050 ãð. 4 > 0, âûïîëíÿþòñÿ ÊÑ 1.31 - 1.33      │

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│ÄàíÀäâÅÑÍ│1.31│ð. 2.1 ñòð. 030 ãð. 3  │ÍÊ ÐÔ    │Çàíèæåíèå íà-│Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │/ ð. 2.1 ñòð. 030 ãð. 4│ñò. 241  │ëîãîâîé áàçû │äîìëåíèå îáîñîáëåííîìó ïîä-│

│         │    │> 600000               │         │ïî ÅÑÍ â ÔÁ, │ðàçäåëåíèþ (ãîëîâíîé îðãà- │

│         │    │                       │         │ÔÔÎÌÑ, ÒÔÎÌÑ │íèçàöèè) Àäâîá î ïðåäñòàâ- │

│         │    │                       │         │è (èëè) çàâû-│ëåíèè äàííûõ ó÷åòà ïî ï. 4 │

│         │    │                       │         │øåíèå ÷èñëåí-│ñò. 243 ÍÊ ÐÔ â îòíîøåíèè  │

│         │    │                       │         │íîñòè ôèçè-  │àäâîêàòîâ, ïåðåõîäèâøèõ â  │

│         │    │                       │         │÷åñêèõ ëèö   │òå÷åíèå íàëîãîâîãî ïåðèîäà │

│         │    │                       │         │äëÿ ðàñ÷åòà  │èç îäíîãî îáîñîáëåííîãî    │

│         │    │                       │         │ÅÑÍ â ÔÁ,    │ïîäðàçäåëåíèÿ Àäâîá â äðó- │

│         │    │                       │         │ÔÔÎÌÑ, ÒÔÎÌÑ │ãîå                        │

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│ÄàíÀäâÅÑÍ│1.32│ð. 2.1 ñòð. 030 ãð. 3  │ÍÊ ÐÔ    │Çàíèæåíèå íà-│Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │/ ð. 2.1 ñòð. 030 ãð. 4│ñò. 241  │ëîãîâîé áàçû │äîìëåíèå îáîñîáëåííîìó ïîä-│

│         │    │<= 600000              │         │ïî ÅÑÍ â ÔÁ, │ðàçäåëåíèþ (ãîëîâíîé îðãà- │

│         │    │                       │         │ÔÔÎÌÑ, ÒÔÎÌÑ │íèçàöèè) Àäâîá î ïðåäñòàâ- │

│         │    │                       │         │è (èëè) çàâû-│ëåíèè äàííûõ ó÷åòà ïî ï. 4 │

│         │    │                       │         │øåíèå ÷èñëåí-│ñò. 243 ÍÊ ÐÔ â îòíîøåíèè  │

│         │    │                       │         │íîñòè ôèçè-  │àäâîêàòîâ, ïåðåõîäèâøèõ â  │

│         │    │                       │         │÷åñêèõ ëèö   │òå÷åíèå íàëîãîâîãî ïåðèîäà │

│         │    │                       │         │äëÿ ðàñ÷åòà  │èç îäíîãî îáîñîáëåííîãî    │

│         │    │                       │         │ÅÑÍ â ÔÁ,    │ïîäðàçäåëåíèÿ Àäâîá â äðó- │

│         │    │                       │         │ÔÔÎÌÑ, ÒÔÎÌÑ │ãîå                        │

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│ÄàíÀäâÅÑÍ│1.33│ð. 2.1 ñòð. 031 ãð. 3  │ÍÊ ÐÔ    │Çàíèæåíèå íà-│Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │/ ð. 2.1 ñòð. 031 ãð. 4│ñò. 241  │ëîãîâîé áàçû │äîìëåíèå îáîñîáëåííîìó ïîä-│

│         │    │<= 600000              │         │ïî ÅÑÍ â ÔÁ, │ðàçäåëåíèþ (ãîëîâíîé îðãà- │

│         │    │                       │         │ÔÔÎÌÑ, ÒÔÎÌÑ │íèçàöèè) Àäâîá î ïðåäñòàâ- │

│         │    │                       │         │è (èëè) çàâû-│ëåíèè äàííûõ ó÷åòà ïî ï. 4 │

│         │    │                       │         │øåíèå ÷èñëåí-│ñò. 243 ÍÊ ÐÔ â îòíîøåíèè  │

│         │    │                       │         │íîñòè ôèçè-  │àäâîêàòîâ, ïåðåõîäèâøèõ â  │

│         │    │                       │         │÷åñêèõ ëèö   │òå÷åíèå íàëîãîâîãî ïåðèîäà │

│         │    │                       │         │äëÿ ðàñ÷åòà  │èç îäíîãî îáîñîáëåííîãî    │

│         │    │                       │         │ÅÑÍ â ÔÁ,    │ïîäðàçäåëåíèÿ Àäâîá â äðó- │

│         │    │                       │         │ÔÔÎÌÑ, ÒÔÎÌÑ │ãîå                        │

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│Äëÿ âñåõ àäâîêàòñêèõ îáðàçîâàíèé âûïîëíÿþòñÿ ÊÑ 1.34 - 1.36                               │

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│ÄàíÀäâÅÑÍ│1.34│ð. 2.1 ñòð. 030 ãð. 3 =│ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │ð. 2.1 ñòð. (031 + 032)│         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │ãð. 3                  │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│1.35│ð. 2.1 ñòð. 030 ãð. 4 =│ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │ð. 2.1 ñòð. 031 ãð. 4  │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │                       │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│1.36│ð. 2.1 ñòð. 040 ãð. 3  │ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │(4) = ð. 2.1 ñòð. (010 │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │+ 020 + 030) ãð. 3 (4) │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│Ðàçäåë 2.2 "Äîõîäû îò ïðîôåññèîíàëüíîé äåÿòåëüíîñòè àäâîêàòîâ, ÿâëÿþùèõñÿ èíâàëèäàìè I,   │

│II èëè III ãðóïïû, âêëþ÷àåìûå â ñòðîêè 0400 - 0440 Ðàçäåëà 2"                             │

├─────────┬────────────────────────────────────────────────────────────────────────────────┤

│         │âíóòðèäîêóìåíòíûå ÊÑ                                                            │

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│ÄàíÀäâÅÑÍ│1.37│ð. 2.2 ñòð. 020 ãð. 6 =│ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │ð. 2.2 ñòð. 020 ãð. (7 │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │+ 8 + 9)               │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│1.38│ð. 2.2 ñòð. 020 ãð. 5 =│ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │ñóììà ð. 2.2 ñòð. 010  │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │ãð. 5                  │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│1.39│ð. 2.2 ñòð. 020 ãð. 6 =│ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │ñóììà ð. 2.2 ñòð. 010  │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │ãð. 6                  │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

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│ÄàíÀäâÅÑÍ│1.40│ð. 2.2 ñòð. 020 ãð. 7 =│ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │ñóììà ð. 2.2 ñòð. 010  │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │ãð. 7                  │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

├─────────┼────┼───────────────────────┼─────────┼─────────────┼───────────────────────────┤

│ÄàíÀäâÅÑÍ│1.41│ð. 2.2 ñòð. 020 ãð. 8 =│ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │ñóììà ð. 2.2 ñòð. 010  │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │ãð. 8                  │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

├─────────┼────┼───────────────────────┼─────────┼─────────────┼───────────────────────────┤

│ÄàíÀäâÅÑÍ│1.42│ð. 2.2 ñòð. 020 ãð. 9 =│ÀΠ      │             │Íàïðàâèòü ïèñüìåííîå óâå-  │

│         │    │ñóììà ð. 2.2 ñòð. 010  │         │             │äîìëåíèå Àäâîá î ïðåäîñòàâ-│

│         │    │ãð. 9                  │         │             │ëåíèè â óñòàíîâëåííûé ñðîê │

│         │    │                       │         │             │ïîÿñíåíèé.  ñëó÷àå ðàñõîæ-│

│         │    │                       │         │             │äåíèé - óêàçàòü ôàêòû íàðó-│

│         │    │                       │         │             │øåíèé èñ÷èñëåíèÿ ÅÑÍ â äî- │

│         │    │                       │         │             │êëàäíîé çàïèñêå íà èìÿ ðó- │

│         │    │                       │         │             │êîâîäèòåëÿ (èëè çàìåñòèòåëÿ│

│         │    │                       │         │             │ðóêîâîäèòåëÿ), îôîðìëÿåìîé │

│         │    │                       │         │             │ïî ðåçóëüòàòàì êàìåðàëüíîé │

│         │    │                       │         │             │ïðîâåðêè ïî ñîâîêóïíîñòè   │

│         │    │                       │         │             │íàðóøåíèé, è äàòü ïðåäëîæå-│

│         │    │                       │         │             │íèÿ î ïðèíÿòèè ñîîòâåòñò-  │

│         │    │                       │         │             │âóþùåãî ðåøåíèÿ ñîãëàñíî   │

│         │    │                       │         │             │ï. 2 ñò. 101 ÍÊ ÐÔ         │

└─────────┴────┴───────────────────────┴─────────┴─────────────┴───────────────────────────┘

 

 

 

 

 

Ïðèëîæåíèå

 

ÑÏÈÑÎÊ ÏÐÈÍßÒÛÕ ÑÎÊÐÀÙÅÍÈÉ

 

Ñîêðàùåíèå

Ïîëíîå íàçâàíèå                 

ÄàíÀäâÅÑÍ

Äàííûå îá èñ÷èñëåííûõ ñóììàõ åäèíîãî ñîöèàëüíîãî    
íàëîãà ñ äîõîäîâ àäâîêàòîâ (Ïðèêàç Ìèíôèíà Ðîññèè   
îò 06.02.2006 N 23í)                                

ÔÁ       

Ôåäåðàëüíûé áþäæåò                                  

ÔÔÎÌÑ    

Ôåäåðàëüíûé ôîíä îáÿçàòåëüíîãî ìåäèöèíñêîãî ñòðàõîâà-
íèÿ                                                  

ÒÔÎÌÑ    

Òåððèòîðèàëüíûé ôîíä îáÿçàòåëüíîãî ìåäèöèíñêîãî     
ñòðàõîâàíèÿ                                         

ÍÊ ÐÔ    

Íàëîãîâûé êîäåêñ Ðîññèéñêîé Ôåäåðàöèè               

ñò.      

Ñòàòüÿ Íàëîãîâîãî êîäåêñà Ðîññèéñêîé Ôåäåðàöèè      

ÀΠ      

Àðèôìåòè÷åñêàÿ îøèáêà                               

ÀäâÎá    

Àäâîêàòñêîå îáðàçîâàíèå (êîëëåãèÿ àäâîêàòîâ, àäâîêàò-
ñêîå áþðî, þðèäè÷åñêàÿ êîíñóëüòàöèÿ)                

íï       

Íàëîãîâûé ïåðèîä                                    

ðÅÑÍ çà  
9 ìåñ.   

Ðàñ÷åò àâàíñîâûõ ïëàòåæåé ïî åäèíîìó ñîöèàëüíîìó íà-
ëîãó äëÿ ëèö, ïðîèçâîäÿùèõ âûïëàòû ôèçè÷åñêèì ëèöàì 
(Ïðèêàç Ìèíôèíà Ðîññèè îò 17.03.2005 N 40í)         

ð.       

Ðàçäåë                                              

ñòð.     

Ñòðîêà                                              

ãð.      

Ãðàôà                                               

 

 






ßíäåêñ öèòèðîâàíèÿ


Èíòåðíåò ïîðòàë îôèöèàëüíûõ ïèñüìåííûõ ðàçúÿñíåíèé îò îðãàíîâ ãîñóäàðñòâåííîé âëàñòè ÐÔ.
Íàñòîÿùèé ïðîåêò ñîçäàí ñïåöèàëüíî äëÿ ðàçúÿñíåíèÿ è ïðàâèëüíîãî ïîíèìàíèÿ Ðîññèéñêîãî çàêîíîäàòåëüñòâà âñåìè ãðàæäàíàìè ÐÔ.
Ïðîåêò ïðèçâàí ïîìî÷ü Âàì â áîðüáå ñ ñóùåñòâóþùåé áþðîêðàòèåé.
Åñëè àäìèíèñòðàöèÿ ïðåäïðèÿòèÿ (ðàáîòîäàòåëü, ïîñòàâùèê óñëóã, ïðîäóêöèè) èëè ÷èíîâíèêè ìåñòíîãî çíà÷åíèÿ ïîïèðàþò Âàøè çàêîííûå ïðàâà, òî ñàìîå ïðàâèëüíîå è âûãîäíîå äëÿ Âàñ ðåøåíèå - íàéòè íà äàííîì ñàéòå ïèñüìî ñ îôèöèàëüíûì ðàçúÿñíåíèåì ïî àíàëîãè÷íîé ïðîáëåìå è ïðåäúÿâèòü åãî Âàøèì "îáèä÷èêàì" ñ öåëüþ âîññòàíîâëåíèÿ ñïðàâåäëèâîñòè è ïîâûøåíèÿ èõ þðèäè÷åñêîé ãðàìîòíîñòè. Ìàòåðèàëû ñàéòà ïîìîãóò òàêæå ñîñòàâèòü Âàì ãðàìîòíîå îáðàùåíèå (æàëîáó, òðåáîâàíèå, çàÿâëåíèå) ñ óêàçàíèåì ìíåíèÿ (ññûëêè íà îôèöèàëüíîå ïèñüìî) âûøåñòîÿùåãî îðãàíà ãîñóäàðñòâåííîé âëàñòè.

Âíèìàíèå!  ñîîòâåòñòâèè ñ Ãðàæäàíñêèì êîäåêñîì ÐÔ íå ÿâëÿþòñÿ îáúåêòàìè àâòîðñêèõ ïðàâ îôèöèàëüíûå äîêóìåíòû ãîñóäàðñòâåííûõ îðãàíîâ è îðãàíîâ ìåñòíîãî ñàìîóïðàâëåíèÿ ìóíèöèïàëüíûõ îáðàçîâàíèé, â òîì ÷èñëå çàêîíû, äðóãèå íîðìàòèâíûå àêòû, ñóäåáíûå ðåøåíèÿ, èíûå ìàòåðèàëû çàêîíîäàòåëüíîãî, àäìèíèñòðàòèâíîãî è ñóäåáíîãî õàðàêòåðà, îôèöèàëüíûå äîêóìåíòû ìåæäóíàðîäíûõ îðãàíèçàöèé, à òàêæå èõ îôèöèàëüíûå ïåðåâîäû. Âñå äîêóìåíòû (ïèñüìà) äàííîãî ðåñóðñà èñõîäÿò îò ãîñóäàðñòâåííûõ îðãàíîâ è èìåþò îôèöèàëüíûé õàðàêòåð, ïîýòîìó âñå îíè íå ñ÷èòàþòñÿ îáúåêòàìè àâòîðñêîãî ïðàâà íà òåððèòîðèè Ðîññèè.  ñâÿçè ñ ýòèì Âû ìîæåòå èñïîëüçîâàòü ëþáûå ìàòåðèàëû äàííîãî ñàéòà áåç êàêèõ-ëèáî îãðàíè÷åíèé è ïî ñâîåìó óñìîòðåíèþ.

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